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(H)=-4.9H^2+58.8H
We move all terms to the left:
(H)-(-4.9H^2+58.8H)=0
We get rid of parentheses
4.9H^2-58.8H+H=0
We add all the numbers together, and all the variables
4.9H^2-57.8H=0
a = 4.9; b = -57.8; c = 0;
Δ = b2-4ac
Δ = -57.82-4·4.9·0
Δ = 3340.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-57.8)-\sqrt{3340.84}}{2*4.9}=\frac{57.8-\sqrt{3340.84}}{9.8} $$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-57.8)+\sqrt{3340.84}}{2*4.9}=\frac{57.8+\sqrt{3340.84}}{9.8} $
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